Stat 200 week 5 homework

NAME__________________                                                                        Score ______ / 50

 

 

STAT 200: Introduction to Statistics

Homework #5: Lesson 8, Sections 1-5 through Lesson 9, Sections 1-2

 

 

1.      (2 points) A claim is made that when parents use the XSORT method of gender selection during in-vitro fertilization, the proportion of baby girls is greater than 0.5.  The latest results show that among 945 babies born to couples using the XSORT method of gender selection, 879 were girls. 

 

a.       (1 point) Express the original claim in symbolic form. 

 

b.      (1 point) Identify the null and alternative hypothesis. 

 

 

2.      (10 points) A 0.05 significance level is used for a hypothesis test of the claim that when parents use the XSORT method of gender selection, the proportion of baby girls is different from 0.5.  Assume that the data consists of 55 girls born in 100 births, so the sample statistic of 0.55 results in a z-score that is 1.00 standard deviation above 0. 

 

a.       (1 point) Identify the null and alternative hypothesis.

 

b.      (1 point) What is the value of α?

 

c.       (1 point) What is the sampling distribution of the sample statistic?

 

d.      (1 point) Is this a two-tailed, left-tailed, or right-tailed test?  Why?

 

e.       (1 point) What is the value of the test statistic?

 

f.       (2 points) What is the P-value?

 

g.      (1 point) What is the critical value?

 

h.      (1 point) What is the area of the critical region?

 

i.        (1 point) What is the result of the hypothesis test (i.e. “Reject the Null Hypothesis” or “Fail to Reject the Null Hypothesis)?  Why?

 

 

3.      (8 points) The data set below contains data from a simple random sample of 100 M&Ms, 8 of which are brown (i.e. 8% or the proportion of 8 out of 100 are brown).  Use a 0.05 significance level to test the claim of the Mars Candy Company that the percentage of brown M&Ms is equal to 13%. 

 

Count

Red

Orange

Yellow

Brown

Blue

Green

1

0.751

0.735

0.883

0.696

0.881

0.925

2

0.841

0.895

0.769

0.876

0.863

0.914

3

0.856

0.865

0.859

0.855

0.775

0.881

4

0.799

0.864

0.784

0.806

0.854

0.865

5

0.966

0.852

0.824

0.840

0.810

0.865

6

0.859

0.866

0.858

0.868

0.858

1.015

7

0.857

0.859

0.848

0.859

0.818

0.876

8

0.942

0.838

0.851

0.982

0.868

0.809

9

0.873

0.863

 

 

0.803

0.865

10

0.809

0.888

 

 

0.932

0.848

11

0.890

0.925

 

 

0.842

0.940

12

0.878

0.793

 

 

0.832

0.833

13

0.905

0.977

 

 

0.807

0.845

14

 

0.850

 

 

0.841

0.852

15

 

0.830

 

 

0.932

0.778

16

 

0.856

 

 

0.833

0.814

17

 

0.842

 

 

0.881

0.791

18

 

0.778

 

 

0.818

0.810

19

 

0.786

 

 

0.864

0.881

20

 

0.853

 

 

0.825

 

21

 

0.864

 

 

0.855

 

22

 

0.873

 

 

0.942

 

23

 

0.880

 

 

0.825

 

24

 

0.882

 

 

0.869

 

25

 

0.931

 

 

0.912

 

26

 

 

 

 

0.887

 

27

 

 

 

 

0.886

 

 

a.       (1 point) Identify the null and alternative hypothesis.

 

b.      (1 point) Is this a two-tailed, left-tailed, or right-tailed test?  Why?

 

c.       (1 point) What is the value of the test statistic?

 

d.      (2 points) What is the P-value?

 

e.       (1 point) What is the critical value?

 

f.       (1 point) What is the area of the critical region?

 

g.      (1 point) What is the result of the hypothesis test (i.e. “Reject the Null Hypothesis” or “Fail to Reject the Null Hypothesis)?  Why did you respond with this answer, and what does it mean?

 

 

4.      (10 points) The data set in problem 3 presents a sample of 100 plain M&M candies that randomly selected (without replacement) from a bag which contained a total of 465 M&M candies.  The weight of each M&M (in grams) is recorded in the table above and in the available Excel Data Set file.  From this simple random sample, there were 19 green M&Ms with a mean of 0.8635 g and a standard deviation of 0.0570.  Use a 0.05 significance level to test the claim that the mean weight of all M&Ms is equal to 0.8535, which is the mean weight required so that M&Ms have the weight printed on the packaged label. 

 

a.       (1 point) Identify the null and alternative hypothesis.

 

b.      (1 point) Is this a two-tailed, left-tailed, or right-tailed test?  Why?

 

c.       (2 points) What is the value of the test statistic?

 

d.      (2 points) What is the P-value?

 

e.       (1 point) What is the critical value?

 

f.       (1 point) What is the area of the critical region?

 

g.      (1 point) What is the result of the hypothesis test (i.e. “Reject the Null Hypothesis” or “Fail to Reject the Null Hypothesis)?  Why did you respond with this answer, and what does it mean?

 

h.      (1 point) Do green M&Ms appear to have weights consistent with the package label?

 

 

5.       (10 points) The Wechsler IQ test is designed so that the mean is 100 and the standard deviation is 15 for the population of normal adults.  Listed below (and in the Excel Data File) are the IQ scores of randomly selected professional pilots.  It is claimed that because the professional pilots are a more homogenous group than the general population (i.e. they are “more alike” than a random group of people), they have IQ scores with a standard deviation less than 15.  Test the claim using a 0.05 significance level.

 

121

116

115

121

116

107

127

98

116

101

130

114

 

a.       (1 point) Identify the null and alternative hypothesis.

 

b.      (1 point) Is this a two-tailed, left-tailed, or right-tailed test?  Why?

 

c.       (2 points) What is the value of the test statistic?

 

d.      (2 points) What is the critical value?

 

e.       (2 points) What is the P-value?

 

f.       (1 point) What is the area of the critical region?

 

g.      (1 point) What is the result of the hypothesis test (i.e. “Reject the Null Hypothesis” or “Fail to Reject the Null Hypothesis)?  Why did you respond with this answer, and what does it mean?

 

 

 

6.      (10 points) Listed below (and in the available Excel Data Set file) are the PSAT and SAT scores from prospective college applicants.  The scores were reported by subjects who responded to a request posted by the web site talk.collegconfidential.com.  There is a claim that higher PSAT scores correlate to higher SAT scores.  Use this data set to argue for or against that claim.

 

PSAT

183

207

167

206

197

142

193

176

SAT

2200

2040

1890

2380

2290

2070

2370

1980

 

a.       (1 point) Identify the null and alternative hypothesis.

 

b.      (1 point) Is this a two-tailed, left-tailed, or right-tailed test?  Why?

 

c.       (2 points) What is the value of the test statistic?

 

d.      (2 points) What is the critical value?

 

e.       (2 points) What is the P-value?

 

f.       (1 point) What is the result of the hypothesis test (i.e. “Reject the Null Hypothesis” or “Fail to Reject the Null Hypothesis)?  Why did you respond with this answer, and what does it mean?

 

g.      (1 point) Is there anything about the data that might make the results questionable?

 

 

 

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